Physics - Fluid Question with Solution | TestHub

Bernoulli's theorem for unit mass of liquid is

$\frac{\mathrm{P}}{\mathrm{\rho }}+\frac{1}{2}{\mathrm{v}}^2=$constant

As the liquid starts flowing, its pressure energy decreases

$\frac{1}{2}{\mathrm{v}}^2=\frac{\mathrm{\Delta }\mathrm{P}}{\mathrm{\rho }}$

$\Rightarrow \mathrm{ }\mathrm{ }\frac{1}{2}{\mathrm{v}}^2=\frac{3.5\times 10^5-3\times 10^5}{10^3}$

$\Rightarrow \mathrm{ }\mathrm{ }{\mathrm{v}}^2=\frac{2\times 0.5\times 10^5}{10^3}$

$\Rightarrow \mathrm{ }{\mathrm{v}}^2=100$

$\Rightarrow \mathrm{ }\mathrm{ }\mathrm{v}=10\mathrm{ }\mathrm{m}/\mathrm{s}$