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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionMedium2 minPYQ_2020

PhysicsMediumsingle choice

Let $^{'} R_{1}$ ' and $^{'} R_{2}$ ' are radii of two mercury drops. A big mercury drop is formed from them under isothermal conditions. The radius of the resultant drop is

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Answer:

Solution:

The Volume of the bigger drop is equal to the sum of the volumes of the smaller drops. $∴ \frac{4}{3} π R^{3} = \frac{4}{3} π R_{1}^{3} + \frac{4}{3} π R_{2}^{3} R = 3 R_{1}^{3} + R_{2}^{3}$

Stream:MHT_CETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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