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PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

The surface tension of water is $0.072 N m^{- 1}$ . The excess pressure inside a water drop, of diameter $1.2 mm$ , is

Answer:

Solution:

$P = \frac{2 S}{r} = \frac{4 S}{D} = \frac{4 \times 0.072}{1.2 \times 1 0^{- 3}} = 240 N m^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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