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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

When a mercury drop of radius 'R', breaks into 'n' droplets of equal size, the radius 'r' of each droplet is

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Solution:

Volume remains constant $∴ n \times \frac{4}{3} π r^{3} = \frac{4}{3} π R^{3}$ $∴ nr^{3} = R^{3}$ $∴ n^{\frac{1}{3}} r = R ∴ r = \frac{R}{n ^{\frac{1}{3}}}$

Stream:MHT_CETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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