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Physics - Fluid Question with Solution | TestHub

PhysicsFluidViscosityMedium2 minPYQ_2018

PhysicsMediumsingle choice

The velocity of water in a river is $18 km / hr$ near the surface. If the river is $5 m$ deep, find the shearing stress between the horizontal layers of water. The co-efficient of viscosity of water $= 1 0^{- 2}$ poise.

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Answer:

Solution:

$η = 1 0^{- 2}$ poise $v = 18 km / h = \frac{18000}{3600} = 5 m / s l = 5 m$ Strain rate $= \frac{v}{l}$ Coefficient of viscosity, $η = \frac{shearing stress}{strain rate} ∴ Shearing stress = η \times strain rate = 1 0^{- 2} \times \frac{5}{5} = 1 0^{- 2} Nm^{- 2}$

Stream:VITEEESubject:PhysicsTopic:FluidSubtopic:Viscosity

⏱ 2mℹ️ Source: PYQ_2018

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