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PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasynumerical

When a long glass capillary tube of radius $0.015 cm$ is dipped in a liquid, the liquid rises to a height of $15 cm$ within it. If the contact angle between the liquid and glass to close to $0 °$ , the surface tension of the liquid, in milliNewton $m^{- 1},$ is $[ρ_{(liqued)} = 900 kg m^{- 3}, g = 10 m s^{- 2}]$ (Given answer in closed integer)

Answer:

101.00

Solution:

Using the concept of rise due to surface tension,

$\frac{2 T}{r} = hρg$

$T = \frac{rhρg}{2} = \frac{15 \times 10^{- 5} \times 15 \times 10^{- 2} \times 900 \times 10}{2} = 101 milliNewton m^{- 1}$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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