Physics - Fluid Question with Solution | TestHub

When the sealed capillary tube is submerged vertically into water, the pressure inside the tube changes For the inside capillary, $$p_1{V}_1=p_2{v}_2$$ $\therefore P_0(lA)=p^{\prime }(l-x)A$ where $p^{\prime }$ is pressure in capillary after being submerged $\therefore$ $$p^{\prime }=\frac{p_{0}l}{l-x}$$ According to question, since level of water inside capillary coincides with outside. $$\begin{array}{l}\therefore p^{\prime }-p_0=\frac{2\gamma }{r}\\ \therefore \frac{p_d}{l-x}-p_0=\frac{2\gamma }{r}=\frac{l}{\left(1+\frac{p_{0}r}{2\gamma }\right)}\end{array}$$