Water flows m a horizontal tube (see figure). The pressure of water changes by $700 N m^{- 2}$ between $A$ and $B$ where the area of cross section are $40 c m^{2}$ and $20 c m^{2},$ respectively. Find the rate of flow of water through the tube. (density of water $= 1000 k g m^{- 3}$ )

Question

TestHub · Accepted Answer

Using equation of continuity 40 V A = 20 V B ⇒ 2 V A = V B Using Bernoulli’s equation P A + 1 2 ρ V A 2 = P B + 1 2 ρ V B 2 ⇒ P A - P B = 1 2 V B 2 - V A 2 ⇒ Δ P = 1 2 1000 V B 2 - V B 2 4 ⇒ Δ P = 500 × 3 V B 2 4 ⇒ V B = Δ P × 4 1500 = 700 × 4 1500 m s Volume flow rate = 20 × 100 × V B = 2732 c m 3 / s

Physics - Fluid Question with Solution | TestHub

Options:

Doubts & Discussion