Physics - Fluid Question with Solution | TestHub

Let mass of the drop $=m$ Weight of the drop = mg It will act downward. The force due to surface tension on the drop $=\sigma 2\pi R$ Where, $R=$ radius of tap If will act in upward direction. The drop of water will detach when $$mg>\sigma 2\pi R$$ $$\begin{array}{l}\text{ But, }m=v\times \rho =\frac{4}{3}{\pi }^{3}pg\\ \therefore \frac{4}{3}{\pi }^3\rho g>\sigma \times 2\pi A\end{array}$$ $$r>{\left[\frac{3}{2}\frac{\sigma \cdot R}{\rho g}\right]}^{1/3}$$ Hence, none of the given options is correct.