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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2021

PhysicsEasysingle choice

What should be the radius of water drop so that excess pressure inside it is $72 Nm^{- 2}$ ? (The surface tension of water $7.2 \times 1 0^{- 2} Nm^{- 1}$ )

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Answer:

Solution:

Excess pressure in a water drop $= \frac{2 T}{R}$ $T = 7.2 \times 1 0^{- 2} Nm^{- 2} ∴ 72 = \frac{2 \times 7.2 \times 1 0 ^{- 2}}{R} ∴ R = \frac{2 \times 7.2 \times 1 0 ^{- 2}}{72} = 2 \times 1 0^{- 3} m = 2 mm$

Stream:MHT_CETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2021

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