The work done in increasing the size of a soap film for 10 cm × 6 m to 10 cm × 11 cm is 3 × 1 0 − 4 J . The surface tension of the film is

Work done = Area increased So, surface tension S T = 2 × ( 10 × 11 − 10 × 6 ) × 1 0 − 4 3 × 1 0 − 4 = 3 × 1 0 − 2 N / m

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PhysicsFluidSurface TensionMedium2 minPYQ_2013

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The work done in increasing the size of a soap film for $10 cm \times 6 m$ to $10 cm \times 11 cm$ is $3 \times 1 0^{- 4} J$ . The surface tension of the film is

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Solution:

$Work done = Area increased So, surface tension S_{T} = \frac{3 \times 1 0 ^{- 4}}{2 \times ( 10 \times 11 - 10 \times 6 ) \times 1 0 ^{- 4}} = 3 \times 1 0^{- 2} N / m$

Stream:JIPMERSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2013

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