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Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousMedium2 minQB

PhysicsMediumnumerical

The vernier shown has zero error. It has $10$ vernier divisions equal to $9$ main scale divisions, and one main scale division is $1 mm$ . Find the magnitude of its zero error in mm.

Reconstructed diagram: source figure lacked vernier ticks. Scale positions inferred from printed zero error and 10 VSD = 9 MSD.

Answer:

0.70

Solution:

$LC = 0.1 mm$ .

The third vernier mark coincides when vernier zero is left of main zero.

Zero error $= - (10 - 3) (0.1) = - 0.7 mm$ .

Its magnitude is $0.7 mm$ .

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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