While measuring acceleration due to gravity by simple pendulum, a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value of the time period. His act

Question

While measuring acceleration due to gravity by simple pendulum, a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value of the time period. His actual percentage error in the measurement of the value of g will be :

TestHub · Accepted Answer

The formula for g is g = 4 π 2 T 2 L ​ . Δg/g = ΔL/L + 2 ΔT/T Percentage error in g is given by 1% + 2 ( 3% ) = 7% . So, the answer is 7% .

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