In the experiment of Ohm's law, a potential difference of 5.0 V is applied across the end of a conductor of length 10.0 c m and diameter of 5.00 mm . The measured current in the conductor is 2.00

Question

In the experiment of Ohm's law, a potential difference of 5.0 V is applied across the end of a conductor of length 10.0 c m and diameter of 5.00 mm . The measured current in the conductor is 2.00 A . The maximum permissible percentage error in the resistivity of the conductor is :-

TestHub · Accepted Answer

R = A ρ ℓ ​ = I V ​ ρ = I ℓ A V ​ = 4 I ℓ π d 2 V ​ ( A = 4 π d 2 ​ ) ∴ ρ Δ ρ ​ = d 2Δ d ​ + V Δ V ​ + I Δ I ​ + ℓ Δ ℓ ​ ρ Δ ρ ​ = 2 ( 5.00 0.01 ​ ) + 5.0 0.1 ​ + 2.00 0.01 ​ + 10.0 0.1 ​ ρ Δ ρ ​ = 0.004 + 0.02 + 0.005 + 0.01 ρ Δ ρ ​ = 0.039 % error = ρ Δ ρ ​ × 100 = 0.039 × 100 = 3.90%.

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