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Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousMedium2 minQB

PhysicsMediumnumerical

A screw gauge has pitch $1 mm$ and $50$ circular divisions. With closed studs, circular division $44$ coincides with the reference line and main-scale zero is not visible. A glass plate gives main-scale reading three divisions and circular reading $26$ . Find corrected thickness in mm.

Answer:

3.64

Solution:

$LC = \frac{1}{50} = 0.02 mm$ .

Zero error $= - (50 - 44) (0.02) = - 0.12 mm$ .

Observed thickness $= 3 + 26 (0.02) = 3.52 mm$ .

True thickness $= 3.52 - (- 0.12) = 3.64 mm$ .

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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