An ideal fluid is flowing in a non-uniform cross-sectional tube $X Y$ (as shown in the figure) from end $X$ to end $Y$ . If $K_{1}$ and $K_{2}$ are the kinetic energy per unit volume of the fluid at $X$ and $Y$ respectively, then the correct option is :
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According to Bernoulli's principle, Kinetic energy per unit volume + Potential energy per unit volume + Pressure = Constant 2 1 ​ ρ V 2 + ρ g h + P = constant Apply Bernoulli's principle at point X and Y , P + K 1 ​ + ρ g ( 0 ) = P + K 2 ​ + ρ g ( h ) K 1 ​ = K 2 ​ + ρ g h K 1 ​ \gtK 2 ​

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