Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousEasy2 minPYQ_2021

PhysicsEasysingle choice

If the length of the pendulum in pendulum clock increases by $0.1 %$ , then the error in time per day is:

Answer:

Solution:

$T = 2 π \sqrt{\frac{l}{g}}$

$T \propto l^{\frac{1}{2}}$

$\frac{Δ T}{T} = \frac{1}{2} \frac{Δ l}{l}$

$\frac{Δ T}{24 \times 3600} = \frac{1}{2} \times \frac{0.1}{100}$

$Δ T = \frac{1}{2} \times \frac{0.1}{100} \times 24 \times 3600$

$Δ T = 43.2 s$

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

Loading discussions...