The current voltage relation of diode is given by I = (e 1000 V/T - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ± 0.

Question

The current voltage relation of diode is given by I = (e 1000 V/T - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ± 0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA ?

TestHub · Accepted Answer

I = e 1000 V / T - 1 mA When I = 5 mA , e 1000 V / T = 6 mA Also, dI = e 1000 V / T × 1000 T · dV = 6 mA × 1000 300 × 0.01 = 0.2 mA

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