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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACParallel AC circuitsMedium2 minQB

PhysicsMediuminteger

An alternating voltage V $_{0}$ = 100 V with angular frequency $ω$ is connected across the capacitor and inductor having X $_{L}$ = 5 $Ω$ and X $_{C}$ = 10 $Ω$ . Find the ratio of current through inductor to AC source.

Answer:

Solution:

The inductor and capacitor currents are opposite in phase.

$I_{L} = \frac{V _{0}}{X _{L}} = 20 A, I_{C} = \frac{V _{0}}{X _{C}} = 10 A$

$I_{source} = ∣ I_{L} - I_{C} ∣ = 10 A$

$\frac{I _{L}}{I _{source}} = 2$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Parallel AC circuits

⏱ 2mℹ️ Source: QB

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