Physics - EMI/AC Question with Solution | TestHub

Current is leading,  it means inductive reactance is more than capacitive reactance

For making power factor to be unity the value of C is to be increased.

$\Rightarrow$another capacitor$C^{\prime }$should be connected in parallel. So in that condition$X_L=X_C$

$\Rightarrow \omega L=\frac{1}{\omega C_{eq}}\Rightarrow C_{eq}=\frac{1}{{\omega }^{2}L}$

$\Rightarrow C+C^{\prime }=\frac{1}{{\omega }^{2}L}\Rightarrow C^{\prime }=\frac{1}{{\omega }^{2}L}-C$

$\Rightarrow C^{\prime }=\frac{1-{\omega }^{2}LC}{{\omega }^{2}L}$