Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACAC current and voltageHard2 minQB

PhysicsHardnumerical

When a $d c$ voltage of $100 V$ is applied to an inductor, a $d c$ current of $5 A$ flows through it. When an ac voltage of $200 V$ peak value is connected to inductor, its inductive reactance is found to be $203 Ω$ . The power dissipated in the circuit is _______ W.

Answer:

250.00

Solution:

For DC voltage
$R = \frac{V}{I} = \frac{100}{5} = 20Ω$
for AC voltage
$X_{L} = 203 Ω R = 20Ω Z = X_{L}^{2} + R^{2} = 3 \times 400 + 400 = 40Ω Power = i_{rms}^{2} R = (\frac{V _{rms}}{Z})^{2} \times R = (\frac{\frac{200}{2}}{40})^{2} \times 20 = 250 W$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...