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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2020

PhysicsEasysingle choice

Two coils are at fixed locations. when coil 1 has no current and the current in coil 2 increases at the rate $15.0 A s^{- 1}$ the emf in coil 1 is $25.0 mV$ , when coil 2 has no current and coil 1 has a current of $3.6 A$ , the flux linkage in coil 2 is

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Answer:

Solution:

Coefficient of mutual induction M is given by

$|M| = \frac{e_{1}}{({di}_{2} / dt)} = \frac{ϕ_{2}}{i_{1}}$

$∴ ϕ_{2} = \frac{e_{1} i_{1}}{({di}_{2} / dt)} = \frac{(25.0 \times 10^{- 3}) (3.6)}{(15)}$

$= 6 \times 1 0^{- 3} Wb$

$= 6 mWb$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2020

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