The square loop has sides of length 2cm. A magnetic field points out of the page and its magnitude is given by $B = (4 t^{2} y) T$ . Emf induced in loop is given by $\frac{x}{10} μ V$ at $t = 2.5 s$ . Find the value of x .

Question

TestHub · Accepted Answer

B = ( 4 t 2 y ) T d A = B ⋅ 2 d y × 1 0 − 2 ϕ = ∫ 0 2 cm ​ 4 t 2 y × 2 × 1 0 − 2 d y = 16 t 2 × 1 0 − 6 e = d t d ϕ ​ = 32 t × 1 0 − 6 e = 32 × 2.5 μ V 10 x ​ = 10 32 × 25 ​ x = 800

Physics - EMI/AC Question with Solution | TestHub

Doubts & Discussion