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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2023
PhysicsEasynumerical

A coil has an inductance of2 Hand resistance of4 Ω. A10 Vis applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be _____×10-2 J

Answer:
625.00
Solution:

The data given is 

L=2 HR=4 ΩV=10 V

Using Ohm's law, V=IR,

 I=10 V4 Ω=52 A

The energy of an inductor is given by 
      E=12LI2=12×2×254=625×10-2 J

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor
2mℹ️ Source: PYQ_2023

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