In an a.c. circuit, voltage and current are given by: V = 100 sin ( 100 t ) V and I = 100 sin ( 100 t + 3 π ) mA respectively. The average power dissipated in one cycle is :

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PhysicsEMI/ACQuality and Power factorMedium2 minQB

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In an a.c. circuit, voltage and current are given by: $V = 100 sin (100 t) V$ and $I = 100 sin (100 t + \frac{π}{3}) mA$ respectively. The average power dissipated in one cycle is :

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Answer:

Solution:

Standard expression of voltage is given by, $V = V_{0} sin (ω t)$ and for current is given by, $I = I_{0} sin (ω t + ϕ)$ . Clearly, $ϕ$ is the phase difference here. From the given expression, $ϕ = \frac{π}{3}$ . Average power dissipated in one cycle is given by,

$P_{a vg} = V_{r m s} I_{r m s} cos (ϕ)$

$= \frac{100}{2} \times \frac{100 \times 1 0 ^{- 3}}{2} \times cos (\frac{π}{3})$

$= \frac{1 0 ^{4}}{2} \times 1 0^{- 3} \times \frac{1}{2}$

$= \frac{10}{4} = 2.5 W$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Quality and Power factor

⏱ 2mℹ️ Source: QB

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