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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsHard2 minQB

PhysicsHardnumerical

Two circuits are shown in figure $(a)$ and $(b)$ . At a frequency of _______ $r a d s^{- 1}$ the average power dissipated in one cycle will be the same in both the circuits.

Answer:

500.00

Solution:

For figure $(a)$

$P_{a vg} = \frac{V _{r m s}^{2}}{R}$

$\frac{v _{r m s}^{2}}{Z ^{2}} \times R = \frac{v _{r m s}^{2}}{R} \times 1$

$R^{2} = Z^{2}$

$25 = ((x_{C} - x_{L})^{2} + 5^{2})^{2}$

$25 = (x_{c} - x_{L})^{2} + 25$

$x_{c} = x_{L} \Rightarrow \frac{1}{ω C} = ω L$

$ω^{2} = \frac{1}{L C} = \frac{1 0 ^{6}}{0.1 \times 40}$

$ω = 500$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

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