Physics - EMI/AC Question with Solution | TestHub

Given:

$$C=2\mu F=2\times 10^{-6}F$$

$$L=0.6mH=0.6\times 10^{-3}H$$

$$V_0=12V,V=6V$$

Initial energy stored in the capacitor:

$$U_0=\frac{1}{2}C{V}_0^2$$

$$U_0=\frac{1}{2}(2\times 10^{-6})(12{)}^2=144\times 10^{-6}J$$

Energy stored in the capacitor at 6 V:

$$U_C=\frac{1}{2}C{V}^2$$

$$U_C=\frac{1}{2}(2\times 10^{-6})(6{)}^2=36\times 10^{-6}J$$

Energy stored in the inductor:

$$U_L=U_0-U_C$$

$$U_L=(144-36)\times 10^{-6}=108\times 10^{-6}J$$

But,

$$U_L=\frac{1}{2}L{I}^2$$

Current in the circuit:

$$\frac{1}{2}(0.6\times 10^{-3})I^2=108\times 10^{-6}$$

$$I^2=\frac{216\times 10^{-6}}{0.6\times 10^{-3}}=0.36$$

$$I=0.6A$$

Answer:

$$\boxed{5X=3.0A}$$