TestHub
TestHub

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2021
PhysicsEasynumerical

A series LCR circuit ofR=5 Ω, L=20 mHandC=0.5 μFis connected across anACsupply of250 V,having variable frequency. The power dissipated at resonance condition is ________×102 W.

Answer:
125.00
Solution:

XL=XC (due to resonance)

Z=R so irms=VZ=VR

V2R=250×2505=125×102 W

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits
2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...