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PhysicsEMI/ACAC current and voltageMedium2 minai-gemini

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A voltage source is given by $V (t) = 20 + 10 sin (100 π t)$ Volts. If this voltage is applied across a pure resistor of $5 Ω$ , what is the RMS current flowing through the resistor?

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Solution:

The RMS value of a voltage $V (t) = V_{D C} + V_{0} sin (ω t)$ is $V_{r m s} = V_{D C}^{2} + \frac{V _{0}^{2}}{2}$ . Here, $V_{D C} = 20 V$ and $V_{0} = 10 V$ . $V_{r m s} = 2 0^{2} + \frac{1 0 ^{2}}{2} = 400 + 50 = 450 V$ . The RMS current is $I_{r m s} = \frac{V _{r m s}}{R} = \frac{450}{5} = \frac{450}{25} = 18 = 32 A$ .

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage

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