Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsMedium2 minQB

PhysicsMediumsingle choice

A LCR circuit is at resonance for a capacitor $C$ , inductance $L$ and resistance $R$ . Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:

Options:

Answer:

Solution:

In resonance $Z = R$ $I = \frac{V}{R} R \to halved \Rightarrow I \to 2 I$
I becomes doubled.

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...