A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure Two resistors R 1 and R 2 are connected across the ends of the rails. There is a uniform magnetic

Question

A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure Two resistors R 1 and R 2 are connected across the ends of the rails. There is a uniform magnetic field B → pointing into the page. An external agent pulls the bar to the left at a constant speed v . The correct statement about the directions of induced currents I 1 and I 2 flowing through R 1 and R 2 respectively is :

TestHub · Accepted Answer

Given, the external agent pulls the bar towards left. According to Lenz's law and Fleming's right hand rule, there will be a motional EMF generated in the bar. The right-hand rule tells us that the magnetic force on positive charges will be in downward direction and the electric equivalent circuit can be drawn as shown below.

So, $I_{1}$ is in the clockwise direction and $I_{2}$ is in the anticlockwise direction.

Physics - EMI/AC Question with Solution | TestHub

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