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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACTransformerMedium2 minQB

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A transformer consisting of $300$ turns in the primary and $150$ turns in the secondary gives output power of $2.2 k W$ . If the current in the secondary coil is $10 A$ , then the input voltage and current in the primary coil are:

Options:

Answer:

Solution:

Assuming 100% efficiency,

$\frac{V _{2}}{V _{1}} = \frac{i _{1}}{i _{2}} = \frac{N _{2}}{N _{1}}$

$\frac{i _{1}}{i _{2}} = \frac{N _{2}}{N _{1}} \frac{i _{1}}{10} = \frac{150}{300} i_{1} = 5 A$

$P = V I 2200 = 5 \times V_{1} V_{1} = 440 V$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Transformer

⏱ 2mℹ️ Source: QB

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