In the circuit shown below, the inductance $L$ is connected to an ac source. The current flowing in the circuit is $I = I_{0} sin ω t$ . The voltage drop $(V_{L})$ across $L$ is
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Question

In the circuit shown below, the inductance L is connected to an ac source. The current flowing in the circuit is I = I 0 ​ sin ω t . The voltage drop ( V L ​ ) across L is NEET 2024 (Re-NEET)

TestHub · Accepted Answer

V L ​ leads current / by 2 π ​ V L ​ = V 0 ​ sin ( ω t + 2 π ​ ) ( ∵ I = I 0 ​ sin ω t ) V 0 ​ = I 0 ​ X L ​ ⇒ V L ​ = 10 X L ​ cos ( ω t ) = 10 ω L cos ( ω t )

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