A telephone wire of length 200 km has a capacitance of 0.014 μ F km - 1 . If it carries an AC frequency of 5 kHz, what should be the value of an inductor required to be connected in series so that the

Question

A telephone wire of length 200 km has a capacitance of 0.014 μ F km - 1 . If it carries an AC frequency of 5 kHz, what should be the value of an inductor required to be connected in series so that the impedance of the circuit is minimum?

TestHub · Accepted Answer

Capacitance of wire C = 0.014 × 10 - 6 × 200 = 2.8 × 10 - 6 F = 2.8 μF For impedance of the circuit to be minimum X L = X C ⇒ 2 π f L = 1 2 π f C L = 1 4 π 2 f 2 C = 1 4 3.14 2 × 5 × 10 3 2 × 2.8 × 10 - 6 = 0.35 × 10 - 3 H = 0.35 m H

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