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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2024

PhysicsEasysingle choice

In a coil, the current changes from $- 2 A$ to $+ 2 A$ in $0.2 s$ and induces an emf of $0.1 V$ . The self inductance of the coil is :

Options:

Answer:

Solution:

$(E m f)_{induced} = - L \frac{d i}{d t}$
In magnitude form, $∣ Emf_{ind} ∣ = (-) L \frac{di}{dt} \Rightarrow 0.1 = \frac{( L ) [ + 2 - ( - 2 )]}{0.2} \Rightarrow L = \frac{0.1 \times 0.2}{4} = 5 mH$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2024

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