Physics - EMI/AC Question with Solution | TestHub

Given: $\varphi =2t^3+4t^2+2t+5,$ & $t=5\mathrm{s}$ By Faraday's law of EMI, we have, $\mathrm{emf}=-\frac{d\varphi }{dt}$ (where, the symbols have their usual meanings) $\begin{array}{rl}e=\left|\frac{d\varphi }{dt}\right|& =\left|\frac{d}{dt}\left(2t^3+4t^2+2t+5\right)\right|\\ & =6t^2+8t+2\end{array}$ $\begin{array}{rl}extAtt& =5s\\ e& =6(5{)}^2+8(5)+2\\ & =192\mathrm{V}\end{array}$