Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACTransformerEasy2 minQB

PhysicsEasysingle choice

A transformer has an efficiency of $80%$ and works at $10 V$ and $4 kW .$ If the secondary voltage is $240 V,$ then the current in the secondary coil is:

Options:

Answer:

Solution:

Efficiency $η = \frac{P _{o u tp u t}}{P _{in p u t}} = \frac{E _{S} I _{S}}{E _{P} I _{P}}$

$\Rightarrow 0.8 = \frac{240 I _{S}}{4000}$

$\Rightarrow I_{S} = \frac{3200}{240} = 13.33 A$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Transformer

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...