Physics - EMI/AC Question with Solution | TestHub

The magnitude of the motional EMF induced in a rod moving in a magnetic field is given by $\text{EMF}=BLv\sin \theta$, where $\theta$ is the angle between the velocity vector and the magnetic field vector. Given $B=0.4\text{ T}$, $L=50\text{ cm}=0.5\text{ m}$, $v=10\text{ m/s}$, and $\theta =30^{\circ }$. Substituting these values, $\text{EMF}=(0.4\text{ T})(0.5\text{ m})(10\text{ m/s})\sin (30^{\circ })=(2.0\text{ V})\times 0.5=1.0\text{ V}$. The magnitude of the induced EMF is 1 V.