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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACParallel AC circuitsEasy2 minPYQ_2020

PhysicsEasysingle choice

At the moment $t = 0$ , when the charge on the capacitor $C_{1}$ is zero, the switch is closed. If $I_{0}$ be the current through inductor at $t = 0$ , then for $t > 0$ (initially $C_{2}$ is uncharged)

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Answer:

Solution:

The maximum current through the inductor is $I_{0}$ .

By conservation of energy,

$\frac{1}{2} L I_{0}^{2} = \frac{1}{2} (C_{1} + C_{2}) V^{2}$

$V = \sqrt{\frac{L}{(C_{1} + C_{2})}} I_{0}$

$Q_{1} = C_{1} V = C_{1} I_{0} \sqrt{\frac{L}{C_{1} + C_{2}}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Parallel AC circuits

⏱ 2mℹ️ Source: PYQ_2020

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