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PhysicsEMI/ACFaraday law/Lenz lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A conducting ring of radius $r$ and resistance $R$ is placed in a region of uniform time varying magnetic field $B$ which is perpendicular to the plane of the ring. If the magnetic field is changing at a rate $α$ , then the current induced in the ring is

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Answer:

Solution:

The magnitude of the induced emf in the ring is
$|ε| = \frac{d ϕ}{d t} = \frac{d}{d t} (B A) = A \frac{d B}{d t} = π r^{2} α$
The induced current in the ring, $I = \frac{|ε|}{R} = \frac{π r^{2} α}{R}$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: PYQ_2020

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