Physics - EMI/AC Question with Solution | TestHub

Current is

$\mathrm{I}=2\sin \mathrm{\omega t} \mathrm{A}$

Voltage is

$\mathrm{E}=2\cos \mathrm{\omega t}=2\sin \left(\mathrm{\omega t}+\frac{\mathrm{\pi }}{2}\right)\mathrm{ }\mathrm{V}$

The phase difference is of$\frac{\pi }{2}$, so power factor is zero. Therefore average power dissipated in the instrument is zero.