In the circuit shown in the figure, a conducting wire $HE$ is moved with a constant speed $v$ towards left. The complete circuit is placed in a uniform magnetic field $\vec{B}$ perpendicular to the plane of circuit inwards. The current in $HKDE$ is

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The potential difference across capacitor V = B v l = constant Therefore, the charge stored in the capacitor is also constant. Thus, the current through the capacitor is zero.

Physics - EMI/AC Question with Solution | TestHub

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