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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACFaraday law/Lenz lawEasy2 minPYQ_2020

PhysicsEasysingle choice

The flux linked with a coil at any instant $' t'$ is given by $ϕ = 10 t^{2} - 50 t + 250 .$ The induced emf at $t = 3 s$ is

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Answer:

Solution:

flux $ϕ = 10 t^{2} - 50 t + 250$

therefore induced emf is

$ε = \frac{- d ϕ}{d t}$

$ε = - (20 t - 50) V$

at $t = 3 s$

$ε = - (20) (3 - 50)$

$ε = - 10 V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: PYQ_2020

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