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PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2020

PhysicsEasysingle choice

Two coils have a mutual inductance $0.005 H .$ The current changes in the first coil according to equation $I = I_{0} \sin (ω t),$ where $I_{0} = 10 A$ and $ω = 100 π rad s^{- 1} .$ The maximum value of emf in the second coil is

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Answer:

Solution:

emf, induced in second coil $e = M \frac{d I}{d t}$

$\Rightarrow e = M \frac{d}{d t} (I_{0} \sin ω t) = M I_{0} ω \cos (ω t)$

$\Rightarrow e = 0.005 \times 10 \times 100 π \cos ω t$

$\Rightarrow e = 5 π \cos ω t, e_{m a x} = 5 π$

(emf is maximum for $\cos ω t = 1$ )

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2020

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