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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

PhysicsEasysingle choice

Find the steady-state current through $L_{1}$ in the figure

Options:

Answer:

Solution:

In steady-state, both inductors will be short circuit and current drawn from the cell is,

$I_{0} = \frac{V_{0}}{R}$

This current will be divided in $L_{1}$ and $L_{2}$ like in parallel resistors

$I_{1} = I_{0} \frac{L_{2}}{L_{1} + L_{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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