Physics - EMI/AC Question with Solution | TestHub

RMS value of A.C is $\begin{array}{l}{\mathrm{I}}_{\mathrm{v}}=\frac{{\mathrm{I}}_0}{\sqrt{2}}=0.707{\mathrm{I}}_0\\ {\mathrm{I}}_0=\text{ peak value }\end{array}$ $\therefore$ it is $70.7\%$ of peak value.