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PhysicsEMI/ACSeries AC CircuitsMedium2 minPYQ_2020

PhysicsMediumsingle choice

In $L C$ circuit the inductance $L = 40 mH$ and capacitance $C = 100 μF .$ If a voltage $V (t) = 10 s i n (314 t)$ is applied to the circuit, the current in the circuit is given as:

Options:

Answer:

Solution:

$z = \sqrt{R^{2} + {(X_{C} - X_{L})}^{2}}$
$R = 0$
$Z = X_{C} - X_{L}$
$= \frac{1}{ω C} - ω L$
$= \frac{1}{314 \times 100 \times 10^{- 6}} - 314 \times 40 \times 10^{- 3}$
$= 31.84 - 12.56$
$= 19.28 Ω$

$i = \frac{V_{0}}{Z} \sin (314 t + \frac{π}{2})$
$∴ i = \frac{V_{0}}{Z} \cos (314 t) \Rightarrow i = \frac{10}{19.28} \cos (314 t)$
$\Rightarrow i = 0.52 \cos (314 t)$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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