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PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020

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A charged capacitor $C = 30 μF$ is connected to an inductor $L = 27 mH$ , then the angular frequency of the system is

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Answer:

Solution:

Given, $C = 30 μ F, = 30 \times 10^{- 6} F, L = 27 m H = 27 \times 10^{- 3} H$

Since, we know, angular frequency,

$ω = \frac{1}{\sqrt{L C}} = \frac{1}{\sqrt{27 \times 10^{- 3} \times 30 \times 10^{- 6}}}$

$= \frac{1}{9 \times 10^{- 4}}$ = $1.1 \times 10^{3} rad s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: PYQ_2020

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