Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minPYQ_2020
PhysicsEasysingle choice

A capacitor of capacitance10 μFis connected to an AC ammeter. If the source voltage varies asV=502sin100t,the reading of the ammeter is

Options:

Answer:
A
Solution:

C=10 μF=10×10-F

V=502sin100t

Reading of ammeterI=VrmsXC

XC=impendence of capacitor

XC=1ωC

I=Vrms1ωC

Vrms=V2=5022=50 V

Reading of ammeter I

=50×100×10×10-6A

=50×10-3 A50 mA

Subject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits
2mℹ️ Source: PYQ_2020

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