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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSelf and mutual inductorEasy2 minPYQ_2016

PhysicsEasysingle choice

For a current carrying inductor, emf associated is $20 mV$ . Now, current through it changes from $6 A$ to $2 A$ in $2 s$ . The coefficient of mutual inductance is

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Answer:

Solution:

$∣ e ∣ = L \frac{dI}{dt} Here, e = 20 m V = 20 \times 1 0^{- 3} V \frac{dI}{dt} = \frac{6 - 2}{2} = 2 A / s L = ? \Rightarrow 20 \times 1 0^{- 3} = L \times 2 ∴ L = 10 \times 1 0^{- 3} H = 10 mH .$

Stream:VITEEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: PYQ_2016

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